(7x^2+6)(6x-5+(9/x))

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Solution for (7x^2+6)(6x-5+(9/x)) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(7*x^2+6)*(6*x+9/x-5) = 0

(7*x^2+6)*(6*x+9*x^-1-5) = 0

6*x+9*x^-1-5 = 0

6*x^1+9*x^-1-5*x^0 = 0

(6*x^2-5*x^1+9*x^0)/(x^1) = 0 // * x^2

x^1*(6*x^2-5*x^1+9*x^0) = 0

x^1

6*x^2-5*x+9 = 0

6*x^2-5*x+9 = 0

DELTA = (-5)^2-(4*6*9)

DELTA = -191

DELTA < 0

x in { } 

1 = 0

7*x^2+6 = 0

7*x^2 = -6 // : 7

x^2 = -6/7

x belongs to the empty set

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